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**[SOLVED] Ideal gases**

an air bubble of volume 20cm^3 is at the bottom of a lake 40m deep where the temp is

4C, the bubble rises to the surface which is at temp 20C, take the temp of the buble to match that of the surrounding water, just as the bubble reaches the surface, what is it's volume?

## Homework Equations

pV=nRT

p(f)V(f)/p(i)V(i)=nRT(f)/nRT(i)

final pressure= 1.01*10^5Pa

V(i)=20x10^-6m^3

T(i)=277K

T(f)=293K

## The Attempt at a Solution

would need to determine the pressure on the bubble at the bottom of the lake, which I can't remember how to determine

p=hp(density)g?

p=40m(1000kg/m^3)9.8m/s^2

p=39.2x10^4

Vf=(T(f)*(p(i)V(i))/(T(i)p(f))

Vf=(293 * 39.2x10^4 * .00002)/(277*101000)

Vf=2297.12/2.7977x10^7=8.2x10^-5m^3

This shows the volume decreased, wouldn't the volume increase?

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